MCQ
The correct increasing order of polarising power is
- A$Ca^{2+} < Mg^{2+} < Be^{2+} < K^{+}$
- B$Mg^{2+} < Be^{2+} < K^{+} < Ca^{2+}$
- C$Be^{2+} < K^{+} < Ca^{2+} < Mg^{2+}$
- ✓$K^{+} < Ca^{2+} < Mg^{2+} < Be^{2+}$
✓
Answer
Correct option: D.
$K^{+} < Ca^{2+} < Mg^{2+} < Be^{2+}$
d
The increasing order of polarising power is $K^{+}
The increasing order of polarising power is $K^{+}
ratio increases and thus polarising power increases. For $B e^{2+}, M g^{2+}, C a^{2+}$, since charge is same and size is in the order of $\mathrm{Ca}^{2+}>M g^{2+}>\mathrm{Be}^{2+}$, the
order of polarising power is $\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}$
Charge of $K^{+}$ is lowest and size is larger than $\mathrm{Ca}^{2+}$ so its polarising power is lowest.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following are meso compounds
Which of the following is an isomer of compound $1$ ?
→$\underset{(1)}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,$
$\underset{(2)}{\mathop{\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$
$\underset{(3)}{\mathop{C{{H}_{3}}-CH=CH-OH}}\,$
Concentration $C{N^ - }$ in $0.1\,M\,HCN$ is $[{K_a} = 4 \times {10^{ - 10}}]$
→In the following sequence of reactions,
→$C{H_3}C{H_2}C{H_2}Br$ $\xrightarrow{{KOH(alc.)}}\,(A)\,\xrightarrow{{HBr}}(B)\,$ $\xrightarrow{{KOH(aq.)}}(C)$ The product $(C)$ is
The prosthetic group of haemoglobin is
Nitrogen can be obtained from air by removing
Ratio of radius of second and first Bohr orbits of $H$ atom
→If a system is at equilibrium the rate of forward to the reverse reaction is
Select the suitable reagent for above conversion.
The denticity of the ligand present in the Fehling's reagent is $..........$.
→