MCQ
The correct increasing order of polarising power is
- A$Ca^{2+} < Mg^{2+} < Be^{2+} < K^{+}$
- B$Mg^{2+} < Be^{2+} < K^{+} < Ca^{2+}$
- C$Be^{2+} < K^{+} < Ca^{2+} < Mg^{2+}$
- ✓$K^{+} < Ca^{2+} < Mg^{2+} < Be^{2+}$
ratio increases and thus polarising power increases. For $B e^{2+}, M g^{2+}, C a^{2+}$, since charge is same and size is in the order of $\mathrm{Ca}^{2+}>M g^{2+}>\mathrm{Be}^{2+}$, the
order of polarising power is $\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}$
Charge of $K^{+}$ is lowest and size is larger than $\mathrm{Ca}^{2+}$ so its polarising power is lowest.
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$(I)$ $CO_2$ $(II)$ $Br_2$ $(III)$ $SnCl_2$ $(IV)$ $HF$ $(V)$ $NMe_3$


$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$
| S.No | Time/s | Total Pressure/(atm) |
| $1.$ | $0$ | $0.1$ |
| $2.$ | $115$ | $0.28$ |
The rate constant of the reaction is_____$\times 10^{-2} \mathrm{~s}^{-1}$ (nearest integer)