MCQ
The correct increasing order of polarising power is
- A$Ca^{2+} < Mg^{2+} < Be^{2+} < K^{+}$
- B$Mg^{2+} < Be^{2+} < K^{+} < Ca^{2+}$
- C$Be^{2+} < K^{+} < Ca^{2+} < Mg^{2+}$
- ✓$K^{+} < Ca^{2+} < Mg^{2+} < Be^{2+}$
ratio increases and thus polarising power increases. For $B e^{2+}, M g^{2+}, C a^{2+}$, since charge is same and size is in the order of $\mathrm{Ca}^{2+}>M g^{2+}>\mathrm{Be}^{2+}$, the
order of polarising power is $\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}$
Charge of $K^{+}$ is lowest and size is larger than $\mathrm{Ca}^{2+}$ so its polarising power is lowest.
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$56\ g$ of nitrogen and $8\ g$ of hydrogen gas are heated in a closed vessel. At equilibrium, $34\ g$ of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively