MCQ
The correct $IUPAC$ name of the following compound is
  • A
    $5-$ chloro $-4-$ methyl $-1-$ nitrobenzene
  • B
    $2-$ methyl $-5-$ nitro $-1-$ chlorobenzene
  • C
    $3-$ chloro $-4-$ methyl $-1-$ nitrobenzene
  • $2-$ chloro $-1-$ methyl $-4-$ nitrobenzene

Answer

Correct option: D.
$2-$ chloro $-1-$ methyl $-4-$ nitrobenzene
d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Chemical nature of the nitrogen oxide compound obtained from a reaction of concentrated nitric acid and $\mathrm{P}_{4} \mathrm{O}_{10}$ (in $4: 1$ ratio $)$ is:
Which set of quantum numbers is not possible for last electron of $'Al' \,\,(Z = 13) :-$ value of $n,l,m,s$ respectively 
Amides may be converted into amines by reaction named after
The compound that inhibits the growth of tumors is
$1-$ Butyne can be distinguished most easily from $2-$ butyne by
Which blue-liquid is obtained on reacting equimolar amounts of two gases at $-30\,^oC$ ?
$\begin{array}{*{20}{c}}
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C = C{H_2} + {{(C{H_3})}_2}CHC{H_3}\xrightarrow[{273\,K}]{{HF}}{C_8}{H_{18}}(A)} 
\end{array}$ Unknown $(A)$ in the above reaction is
At low temperatures, the slow addition of molecular bromine to $CH_2 = CH-CH_2-C \equiv CH$ gives :-
Molar heat of neutralization of $NaOH$ with $HCl$ in comparison to that of $KOH$ with $HN{O_3} $ is
$20\,mL$ of $0.1\,M\,NH _{4} OH$ is mixed with $40\,mL$ of $0.05\,M\,HCl$. The $pH$ of the mixture is nearest to.(Given: $K _{ b }\left( NH _{4} OH \right)=1 \times 10^{-5}, \log 2=0.30$,$\log 3=0.48, \log 5=0.69, \log 7=0.84$,$\log 11=1.04)$