Download App

STD 11 - 8.3. Organic chemistry purification and characterization — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 8.3. Organic chemistry purification and characterization4 Marks
MCQ
The correct match between items $I$ and $II$ is
Item $-I$ (Mixture) Item $-II$ (Separation method)
$(a)$ $H_2O :$ Sugar $p.$ Sublimation
$(b)$ $H_2O :$ Aniline $q.$ Recrystallization
$(c)$ $H_2O :$ Toluene $r.$ Stem distillation
  $s.$ Differential extraction
  • A
    $a - d, b -r, c -p$
  • ✓
    $a -q, b -r, c -s$
  • C
    $a -r, b -p, c -s$
  • D
    $a -q, b -r, c -p$
✓

Answer

Correct option: B.
$a -q, b -r, c -s$
b
(mixture) $\quad\quad\quad\quad$ (seperation method)

$H _2 O : \text { Sugar } \Rightarrow \text { Recrystallization }$

$H _2 O : \text { Aniline } \Rightarrow \text { Steam distillation }$

$H _2 O \text { : Toluene } \Rightarrow \text { Differential extraction }$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Assertion : The normality of $0.3\, M$ aqueous solution of $H_3PO_3$ is equal to $0.6\, N$.
Reason : Equivalent weight of $H_3PO_3 = \frac{Molecular\, weight\, of\, H_3PO_3}{3}$
→
In the reaction $3Mg + {N_2} \to M{g_3}{N_2}$
→
The highest amount of $s-$ character is observed in
→
In case of hydrogen atom when electron falls from higher level to $M$ shell, the corresponding spectral line will form the part of :
→
Which one is electrophilic addition
→
Which is wrong statement?
→
Among the following, total number of meta directing functional groups is__________ (Integer based)

$ -\mathrm{OCH}_3,-\mathrm{NO}_2,-\mathrm{CN},-\mathrm{CH}_3-\mathrm{NHCOCH}_3, $

$ -\mathrm{COR},-\mathrm{OH},-\mathrm{COOH},-\mathrm{Cl}$

→
The reaction is called $\begin{array}{*{20}{c}}
  {2C{H_3} - C - O{C_2}{H_5}} \\ 
  {||\,\,\,} \\ 
  {O\,\,\,} 
\end{array}$ ${\xrightarrow{{{C_2}{H_5}ONa}}}$  $\begin{array}{*{20}{c}}
  {C{H_3} - C - C{H_2} - C - O{C_2}{H_5}} \\ 
  {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,} \\ 
  {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,} 
\end{array}$ $ + \,{C_2}{H_5}OH$
→
The heat $Q$ for a reaction at constant volume is equal to
→
The correct order of the calculated spin-only magnetic moments of complexs $(A)$ to $(D)$ is

$(A)$ $\mathrm{Ni}(\mathrm{CO})_{4}$

$(B)$ $\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{2}$

$(C)$ $\mathrm{Na}_{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]$

$(D)$ $\mathrm{PdCl}_{2}\left(\mathrm{PPh}_{3}\right)_{2}$

→