MCQ
The correct name for the complex ion $[CoCl(ONO)(en)_2]^+$ is
  • A
    chlorobis(ethylenediamine)nitrito $-O-$ cobaltate $(III)$ ion
  • B
    chlorodiethyldiaminenitrito $-O-$ cobalt $(III)$ ion
  • chloronitrito $-O-$ diethyldiamine cobaltate $(III)$ ion
  • D
    chlorobis(ethylenediamine)nitrito $-O-$ cobalt $(III)$ ion

Answer

Correct option: C.
chloronitrito $-O-$ diethyldiamine cobaltate $(III)$ ion
c
$C.N$ of metal $= 6$ so geometry will be octahedral not tetrahedral

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.

Assertion $(A)$ : Haloalkanes react with $\mathrm{KCN}$ to form alkyl cyanides as a main product while with $\mathrm{AgCN}$ form isocyanide as the main product.

Reason $(R)$ : $\mathrm{KCN}$ and $\mathrm{AgCN}$ both are highly ionic compounds.

In the light of the above statement, choose the most appropriate answer from the options given below:

If the concentration of $OH^-$ ions in the reaction

$Fe(OH)_{3(s)} \rightleftharpoons  Fe^{3+}_{(aq)} + 3OH^-_{(aq)}$

is decreased by $1/4$ times, then equilibrium concentration of $Fe^{3+}$ will increase by.....$ times$

Number of cross products in the given reaction $:\ce{CH_3COOC_2H_5 + C_6H_5 -CH_2 -COOC_2H_5} \mathop {\xrightarrow{{{C_2}{H_5}ONa}}}\limits_{{C_2}{H_5}OH} $
$[Cr(H_2O)_6]Cl_3$ (At. no. of $Cr = 24$) has a magnetic moment of $3.83\, B.M.$ The correct distribution of $3d$ electrons in the chromium of the complex is
Which one of the following is reducing sugar?
The binding of oxygen by haemoglobin $(Hb)$ forming $(HbO_2)$, is partially regulated by the concentration of $H_3O^+$ and dissolved $CO_2$ in blood.

$Hb{O_2} + {H_3}{O^ + }C{O_2} \rightleftharpoons \left( {{H^ + } - Hb - C{O_2}} \right) + {O_2} + {H_2}O$

Release of $O_2$ is favoured when there is

$B$ has a smaller first ionization enthalpy than $Be$. Consider the following statements :

$(I)$ It is easier to remove $2 \mathrm{p}$ electron than $2 \mathrm{s}$ electron

$(II)$ $2 \mathrm{p}$ electron of $\mathrm{B}$ is more shielded from the nucleus by the inner core of electrons than the $2 s$ electrons of $Be.$

$(III)\; 2 s$ electron has more penetration power than $2 \mathrm{p}$ electron.

$(IV)$ atomic radius of $\mathrm{B}$ is more than $\mathrm{Be}$

(Atomic number $\mathrm{B}=5, \mathrm{Be}=4$ )

The correct statements are

Consider the above reaction. The number of $\pi$ electrons present in the product ' $P$ ' is ...... .
The total number of 'sigma' and $'Pi'$ bonds in $2$ -oxohex-$4$-ynoic acid is. . . . . . .
Carbon and oxygen combine to form two oxides, carbon monoxide and carbon dioxide in which the ratio of the weights of carbon and oxygen is respectively $12 : 16$ and $12 : 32$. These figures illustrate the