MCQ
The correct order of basicity of the given compounds is:
  • A
    CH3​CH2​NH2​ < HO(CH2​)3​NH2 ​< HO(CH2​)2​NH2​.
  • B
    CH3​CH2​NH2​ < HO(CH2​)3​NH2​ > HO(CH2​)2​NH2​.
  • C
    CH3​CH2​NH2​ > HO(CH2​)3​NH​> HO(CH2​)2​NH2​.
  • D
    CH3​CH2​NH2​ > HO(CH2​)3​NH2​ < HO(CH2​)2​NH2​.
     

Answer

  1. CH3​CH2​NH2​ > HO(CH2​)3​NH​> HO(CH2​)2​NH2​.

Explanation:

The correct order of basicity of the given compounds is as follows:

CH3​CH2​NH2​ > HO(CH2​)3​NH​> HO(CH2​)2​NH2

OH group is an electron withdrawing group and hence, it increases the partial positive charge on N atom.

Therefore, lone pair of N cannot be easily donated and also, the basicity decreases.

As the number of carbon atoms between −OH group and amino group increases, the electron withdrawing capacity of −OH group on amine N decreases and basicity increases.

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