MCQ
The correct order of bond angle
  • A
    $PF_3 < PCl_3 < PBr_3 > PI_3$
  • $PF_3 < PCl_3 < PBr_3 < PI_3$
  • C
    $PF_3 > PCl_3 > PBr_3 > PI_3$
  • D
    $PF_3 > PCl_3 < PBr_3 > PI_3$

Answer

Correct option: B.
$PF_3 < PCl_3 < PBr_3 < PI_3$
b
$\mathrm{PI}_{3}>\mathrm{PBr}_{3}>\mathrm{PCl}_{3}>\mathrm{PF}_{3}$

If $\mathrm{C.A}$. $=$ same Hybridisation same

$L.P.$  $=$ same                  Bond angle $\propto$ size of side atom

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