MCQ
The correct order of bond angle
- A$PF_3 < PCl_3 < PBr_3 > PI_3$
- ✓$PF_3 < PCl_3 < PBr_3 < PI_3$
- C$PF_3 > PCl_3 > PBr_3 > PI_3$
- D$PF_3 > PCl_3 < PBr_3 > PI_3$
✓
Answer
Correct option: B.
$PF_3 < PCl_3 < PBr_3 < PI_3$
b
$\mathrm{PI}_{3}>\mathrm{PBr}_{3}>\mathrm{PCl}_{3}>\mathrm{PF}_{3}$
$\mathrm{PI}_{3}>\mathrm{PBr}_{3}>\mathrm{PCl}_{3}>\mathrm{PF}_{3}$
If $\mathrm{C.A}$. $=$ same Hybridisation same
$L.P.$ $=$ same Bond angle $\propto$ size of side atom
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Select process in which $SO_2$ is Not evolved:
→In the following reactions, the major product $W$ is
→The heat of reaction does not depend upon
To deposit one gm equivalent of an element at an electrode, the quantity of electricity needed is
$CH_2 = CH - CH = CH - CH = CH_2$
How many geometrical isomers are possible for this compound ?
→How many geometrical isomers are possible for this compound ?
Which of the following statements is correct about the given reaction
→$4F{e_{(s)}} + 3{O_{2(g)}} \to 2F{e_2}{O_{3(s)}}$
Total no. of vacant orbitals in valence shell of sulphur when it undergoes formation of $SF_4$
→$CH_3-CH_2-I$ $\xrightarrow{{NaCN}}A\xrightarrow[{Partial\,hydrolysis}]{{^\Theta OH}}B\xrightarrow[{B{r_2}}]{{NaOH}}C,$ Product $'C'$ is
→Which of the following outer orbital complex has maximum number of unpaired electron
$A$ is
→