MCQ
The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?
- A$N_2 > O_2^- > O_2$
- B$O_2^- > O_2 > N_2$
- ✓$N_2 > O_2 > O_2^-$
- D$O_2 > O_2^- > N_2$
Since higher bond order implies higher bond dissociation energy hence the correct orde will be
$N_2 > O_2 > O_2^-$
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Statement $I$ : The correct order of first ionization enthalpy values of $\mathrm{Li}, \mathrm{Na}, \mathrm{F}$ and $\mathrm{Cl}$ is $\mathrm{Na}<\mathrm{Li}<\mathrm{Cl}<\mathrm{F}$.
Statement $II$ : The correct order of negative electron gain enthalpy values of $\mathrm{Li}, \mathrm{Na}, \mathrm{F}$ and $\mathrm{Cl}$ is $\mathrm{Na}<\mathrm{Li}<\mathrm{F}<\mathrm{Cl}$
In the light of the above statements, choose the correct answer from the options given below :