MCQ
The correct order of $Cl-O$ bond order is
- A$ClO_3^-< ClO_4^- < ClO_2^-< ClO^-$
- B$ClO^-< ClO_4^-< ClO_3^-< ClO_2^-$
- ✓$ClO^-< ClO_2^-< ClO_3^-< ClO_4^-$
- D$ClO_4^-< ClO_3^-< ClO_2^-< ClO^-$
$ClO_2^-$ $B.O.=1.5$
$ClO_3^-$ $B.O.=1.66$
$ClO_4^-$ $B.O=1.75$
$OR$
$Cl{O^ - } < ClO_2^ - < ClO_3^ - < ClO_4^ - $
$B.O.$ $1.0$ $1.5$ $1.66$ $1.75$
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Statement$-I :\, 2 -$methylbutane on oxidation with $KMnO _{4}$ gives $2 -$methylbutan$-2-$ol.
Statement$-II :$ $n-$alkanes can be easily oxidised to corresponding alcohol with $KMnO _{4}$.
Choose the correct option:
$P : 10\ ml, 0.1\ M\ NaOH + 5\ ml, 0.1\ M\ HCl$
$Q : 10\ ml, 0.1\ M\ NaOH + 15\ ml, 0.1\ M\ CH_3COOH$
$R : 10\ ml, 0.1\ M\ NH_3 + 10\ ml, 0.1\ M\ NH_4Cl$
$S : 10\ ml, 0.05\ M\ NaF + 5\ ml, 0.1\ M\ HF$
Which of above solutions act as buffer