STD 11 - 3. Classification of elements and periodicity in properties — NEET STD 11 Science — Question

$A ^{+}( g ) \rightarrow A ^{2+}+ e ^{-}$

$IE _2$ is affected by the size, effective nuclear charge and electronic configuration. So, on moving from $N$ to $Ne$ size of ion decreases, thereby increasing the $IE.$

$\rightarrow F ^{+}$is having less $IE _2$ than $O ^{+}$due to the interelectronics repulsion due to its' high electronegativity, it requires comparatively less energy to remove $e ^{-}$from its' outer shell.

Thus, the correct order is: $Ne \,>\, O \,>\, F\, >\, N$