MCQ
The correct order of $\left[ FeF _6\right]^{3-},\left[ CoF _6\right]^{3-},\left[ Ni ( CO )_4\right]$ and $\left[ Ni ( CN )_4\right]^{2-}$ complex species based on the number of unpaired electrons present is :
  • A
    $\left[ FeF _6\right]^{3-}>\left[ CoF _6\right]^{3-}>\left[ Ni ( CN )_4\right]^{2-}>\left[ Ni ( CO )_4\right]$
  • B
    $\left[ Ni ( CN )_4\right]^{2-}>\left[ FeF _6\right]^{3-}>\left[ CoF _6\right]^{3-}>\left[ Ni ( CO )_4\right]$
  • C
    $\left[ CoF _6\right]^{3-}>\left[ FeF _6\right]^{3-}>\left[ Ni ( CO )_4\right]>\left[ Ni ( CN )_4\right]^{2-}$
  • $\left[ FeF _6\right]^{3-}>\left[ CoF _6\right]^{3-}>\left[ Ni ( CN )_4\right]^{2-}=\left[ Ni ( CO )_4\right]$

Answer

Correct option: D.
$\left[ FeF _6\right]^{3-}>\left[ CoF _6\right]^{3-}>\left[ Ni ( CN )_4\right]^{2-}=\left[ Ni ( CO )_4\right]$
(D) $\left[ FeF _6\right]^{3-}>\left[ CoF _6\right]^{3-}>\left[ Ni ( CN )_4\right]^{2-}=\left[ Ni ( CO )_4\right]$
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