MCQ
The correct order of the first ionization enthalpy is
- A$\mathrm{Al}>\mathrm{Ga}>\mathrm{Tl}$
- B$\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$
- C$\mathrm{B}>\mathrm{Al}>\mathrm{Ga}$
- ✓$\mathrm{Tl}>\mathrm{Ga}>\mathrm{Al}$
($ii$) due to scandide contraction Ga has more $I.E$. as compared to $\mathrm{A} \ell$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})$
is $\mathrm{K}_{\mathrm{C}}=4.9 \times 10^{-2}$. The value of $\mathrm{K}_{\mathrm{C}}$ for the reaction given below is
$2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ is
