MCQ
The correct order of the strength of $H-$ bonds is
- ✓$H ... F > H ... O > H ... N$
- B$H . .. N > H . . . O > H . . . F$
- C$H ... O > H ... N > H ... F$
- D$H . . . F > H . . . N > H . . . O$
✓
Answer
Correct option: A.
$H ... F > H ... O > H ... N$
a
The strength of $H$ - bond decreases in the following order $H \ldots . F \,>\, H \ldots . O\, >\, H....N$. It can be explained as below. The size of electronegative atoms should be small. The smaller the size of electronegative atoms, the greater is the attraction for the bonded electron pair. This causes greater polarity in the $H$ and the electronegative atom, resulting in stronger $H$ - bonding. The size of $F , O , N$ in the following order.
The strength of $H$ - bond decreases in the following order $H \ldots . F \,>\, H \ldots . O\, >\, H....N$. It can be explained as below. The size of electronegative atoms should be small. The smaller the size of electronegative atoms, the greater is the attraction for the bonded electron pair. This causes greater polarity in the $H$ and the electronegative atom, resulting in stronger $H$ - bonding. The size of $F , O , N$ in the following order.
$F \,<\, O \,<\, N$
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