The correct order towards bond angle is - Vidyadip

MCQ

The correct order towards bond angle is

A
$sp < s{p^2} < s{p^3}$
B
$s{p^2} < sp < s{p^3}$
✓
$s{p^3} < s{p^2} < sp$
D
Bond angle does not depend on hybridisation

✓

Answer

Correct option: C.

$s{p^3} < s{p^2} < sp$

(c)Increasing order of bond angle is $\mathop {s{p^3}}\limits_{109^o } < \mathop {s{p^2}}\limits_{120^o } < \mathop {sp}\limits_{180^o } $.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

An element $(X)$ forms compounds of the formula $XC{l_3},$ ${X_2}{O_5}$ and $C{a_3}{X_2},$ but does not form $XC{l_5}$, which of the following is the element $X$

The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product $'A'$. The reaction $1\, mol$ of $'A'$ with excess of $AgNO _{3}$ in aqueous medium gives ............... mol$(s)$ of $Ag$. (Round off to the Nearest Integer).

Anisole on cleavage with $HI$ gives:

$2\ gm$ of benzoic acid ( $C_6H_5COOH$ ) dissolved in $25\ gm$ of benzene shown a depression in freezing point equal to $1.62\ K$ . Molal depression constant for benzene is $4.9\ KKg\ mol^{-1}$ . The $\%$ of benzoic acid in dimeric form is ......... $\%.$

Which of the following is true when components forming an ideal solution are mixed

Which of the following is oxidised by $KMn{O_4}$

$1-$ Phenoxypropane is treated with excess of conc. $HI$ at $0\,^oC$ and the mixture of products is treated with thionyl chloride. The products formed are

$pH$ of a solution is $9.5. $ The solution is

On treating a mixture of two alkyl halides with sodium metal in dry ether, $ 2-$ methyl propane was obtained. The alkyl halides are

Le-Chatelier principle is not applicable to