MCQ
The correct reactivity order for $E_2$ reaction with alcoholic $KOH$ will be
  • $i > ii > iii$
  • B
    $ii > iii > i$
  • C
    $i > iii > ii$
  • D
    $iii > i > ii$

Answer

Correct option: A.
$i > ii > iii$
a
More stable alkene will be major product

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