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STD 12 - 5. Magnetism and matter — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 5. Magnetism and matter4 Marks
MCQ
The correct relation is

$B_H$ $=$ Horizontal component of earth's magnetic field;  $B_V$ $=$ Vertical component of earth's magnetic field and $B  =$  Total intensity of earth's magnetic field

  • A
    $B = \frac{{{B_V}}}{{{B_H}}}$
  • B
    $B = {B_V} \times {B_H}$
  • ✓
    $|B| = \sqrt {B_H^2 + B_V^2} $
  • D
    $B = {B_H} + {B_V}$
✓

Answer

Correct option: C.
$|B| = \sqrt {B_H^2 + B_V^2} $
c
(c) Horizontal and vertical components of earth's magnetic field are $B_{h}$ and $B_{v}$ respectively.

We know that $B_{h}=B \cos \delta$

where $B$ is the earth's total magnetic field and $\delta$ is the angle of dip.

Also, $B_{v}=B \sin \delta$

$\Longrightarrow B^{2}=B_{h}^{2}+B_{v}^{2}$

$\Longrightarrow  B=\sqrt{B_{h}^{2}+B_{v}^{2}}$

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