MCQ
The correct relation is
- ✓$r = \frac{{2T\,\cos \theta }}{{hdg}}$
- B$r = \frac{{hdg}}{{2T\,\cos \theta }}$
- C$r = \frac{{2T\,dgh}}{{\cos \theta }}$
- D$r = \frac{{T\cos \theta }}{{2hdg}}$
✓
Answer
Correct option: A.
$r = \frac{{2T\,\cos \theta }}{{hdg}}$
a
(a) $h=\frac{2 T \cos \theta}{r d g}$
(a) $h=\frac{2 T \cos \theta}{r d g}$
$r=\frac{2 T \cos \theta}{h d g}$
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