MCQ
The correct sequence of decrease in the bond angle of the following hybrides is
- ✓$N{H_3} > P{H_3} > As{H_3} > Sb{H_3}$
- B$N{H_3} > As{H_3} > P{H_3} > Sb{H_3}$
- C$Sb{H_3} > As{H_3} > P{H_3} > N{H_3}$
- D$P{H_3} > N{H_3} > As{H_3} > Sb{H_3}$
$N{H_3} > P{H_3} > As{H_3} > Sb{H_3}$
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$3HCHO+A\xrightarrow[{{40}\,^{o}}C]{N{{a}_{2}}C{{O}_{3}}}\underset{(82\%)}{\mathop{(B)}}$
Product $(B)$ of the above reaction is
[Given : ${E^0}_{Zn/Z{n^{ + 2}}} = 0.76\,V,$
${E^0}_{Cu/C{u^{ + 2}}} = - 0.34\,V,\,\frac{{2.303\,RT}}{F} = 0.06,\log 2 = 0.30]$
Select the incorrect option is

