MCQ
The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:
  • $5,0,0,+\frac{1}{2}$
  • B
    $5,0,1,+\frac{1}{2}$
  • C
     $5,1,0,+\frac{1}{2}$
  • D
     $5,1,1,+\frac{1}{2}$

Answer

Correct option: A.
$5,0,0,+\frac{1}{2}$
a
$ \mathrm{Rb}=[\mathrm{Kr}] 5 \mathrm{~s}^1 $

$ \mathrm{n}=5 $

$ l=0 $

$ \mathrm{~m}=0 $

$ \mathrm{~s}=+1 / 2 \text { or }-1 / 2$

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