MCQ
The correct stability order of the following resonance structures is
- A$(I) > (II) > (IV) > (III)$
- ✓$(I) > (III) > (II) > (IV)$
- C$(II) > (I) > (III) > (IV)$
- D$(III) > (I) > (IV) > (II)$
✓
Answer
Correct option: B.
$(I) > (III) > (II) > (IV)$
b
The greater the number of covalent bonds, the greater the stability since more atoms will have complete octets.
The greater the number of covalent bonds, the greater the stability since more atoms will have complete octets.
The structure with the least number of formal charges is more stable.
The structure with the least separation of formal charge is more stable.
A structure with a negative charge on the more electronegative atom will be more stable.
Positive charges on the least electronegative atom (most electropositive) is more stable
Resonance forms that are equivalent have no difference in stability and contribute equally (eg. benzene)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Assign $A, B, C, D$ from given type of reaction. $XeF_4 +H_2O \longrightarrow Xe + XeO_3 + HF + O_2$
→The correct order of a dipole moment is :
The correct order of dipole moment is :
The chemical name of borax is
The hottest region of Bunsen flame shown in the figure below is :
The newmann projection formula of most stable conformation of $3-$ hydroxypropanal is gauche. It is stable due to
→For melting of $3 $ moles of water at ${0\,^o}C$ the $\Delta {G^o}$ is
→Identify the correct order of solubility in aqueous medium.
For the following reaction in gaseous phase $CO\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \to C{O_2}\left( g \right),{K_p}/{K_c}$ is
→The reagent $X$ in the reactions ${(C{H_3})_3}CCH = C{H_2}\mathop {\xrightarrow{X}}\limits_{THF} Y\mathop {\xrightarrow{{NaB{H_4}}}}\limits_{NaOH} $$\mathop {\mathop {{{(C{H_3})}_3} - C - CH - C{H_3}}\limits_{|\,\,\,\,\,\,\,\,\,\,\,\,\,} }\limits_{OH\,\,\,\,\,\,} $
→