MCQ
The correct statement regarding $SO_2$ molecule is
- Atwo $p \pi - d \pi$ bond
- Bmolecule bas $2$ lone pair, $2 \sigma$ bonds and $2 \pi$ bonds
- Ctwo $p \pi - p \pi$ bonds
- ✓one $p \pi - p \pi$ and one $p \pi - d \pi$ bond
✓
Answer
Correct option: D.
one $p \pi - p \pi$ and one $p \pi - d \pi$ bond
d
$\mathrm{SO}_{2}$ molecule has one $\mathrm{p} \pi-\mathrm{p} \pi$ bond and one $\mathrm{p} \pi-\mathrm{d} \pi$ bond
$\mathrm{SO}_{2}$ molecule has one $\mathrm{p} \pi-\mathrm{p} \pi$ bond and one $\mathrm{p} \pi-\mathrm{d} \pi$ bond
$\mathrm{SO}_{2}=6+6(2)=18 \mathrm{e}-16 \mathrm{e}=2 \mathrm{e} \rightarrow 1$ lone pair
$\rightarrow \mathrm{G} . \mathrm{S}=[\mathrm{Ne}] 3 \mathrm{s}^{2} 3 \mathrm{p}^{4}$
2 Unpaired electron $1^{\text {st }}$ E.S. $=[\mathrm{Ne}] 3 \mathrm{s}^{2} 3 \mathrm{p}^{3} 3 \mathrm{d}^{1}$
4 unpaired electron $\mathrm{O} \rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{4}$
$\rightarrow$ Geometry of $\mathrm{SO}_{2}$ is BENT/ANGULAR
$\rightarrow$ one $\mathrm{p} \pi-\mathrm{p} \pi$ and one $\mathrm{p} \pi-\mathrm{d} \pi$ Bond
$\rightarrow 2 \pi$ Bonds
$\rightarrow 1$ lone pair on the central atom.
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