The critical angle for total internal reflection of light going f… - Vidyadip

MCQ

The critical angle for total internal reflection of light going from medium $I$ to medium $II$ is given by the relation tan $i_C=\frac {5}{9}$ . The refractive index of the medium $I$ with respect to the medium $II$ is

A
$1.8$
B
$1.6$
C
$\frac {\sqrt {156}}{5}$
✓
$\frac {\sqrt {106}}{5}$

✓

Answer

Correct option: D.

$\frac {\sqrt {106}}{5}$

d
$\tan c=\frac{5}{9}$

$\sin c=\frac{1}{\mu}=\frac{5}{\sqrt{106}}$

$\mu=\frac{\sqrt{106}}{5}$

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