MCQ
- ✓$10 A$
- B$20 A$
- C$4 A$
- D$40 A$
✓
Answer
Correct option: A.
$10 A$
(a) : The equivalent circuit diagram of the given network is as shown in figure.
It is a balanced Wheatstone bridge, hence no current flows through arm $C D$. Therefore resistance across arm $C D$ becomes ineffective.
Now, equivalent resistance between terminals $A$ and $B$ is,
$
R=\frac{8 \times 8}{8+8}=4 \Omega
$
Current in the circuit, $I=\frac{V}{R}$
$
\therefore I=\frac{40}{4}=10 A
$
It is a balanced Wheatstone bridge, hence no current flows through arm $C D$. Therefore resistance across arm $C D$ becomes ineffective.
Now, equivalent resistance between terminals $A$ and $B$ is,
$
R=\frac{8 \times 8}{8+8}=4 \Omega
$
Current in the circuit, $I=\frac{V}{R}$
$
\therefore I=\frac{40}{4}=10 A
$
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