
$\frac{1}{{{R_p}}} = \frac{1}{3} + \frac{1}{6} = \frac{{2 + 1}}{6} = \frac{3}{6}$
$ \Rightarrow $ ${R_p} = 2\,\Omega $
$ \Rightarrow $ $I = \frac{2}{2} = 1\,A$



$(i)$ The equivalent e.m.f. is smaller than either of the two $e.m.f.$ is
$(ii)$ The equivalent internal resistance is smaller than either of the two internal resistances