MCQ
The $d-$orbital involved in $s{p^3}d$ hybridisation is
- ✓${d_{{x^2} - {y^2}}}$
- B${d_{xy}}$
- C${d_{{z^2}}}$
- D${d_{zx}}$`
✓
Answer
Correct option: A.
${d_{{x^2} - {y^2}}}$
(a) $ds{p^3}$ or $s{p^3}d$: one ${s^ + }$ three ${p^ + }$ one $d({d_{{z^2}}})$.
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