MCQ
The de-Broglie wavelength of a tennis ball of mass $60 \,g$ moving with a velocity of $10\, metres$ per second is approximately
- ✓${10^{ - 33}}\,metres$
- B${10^{ - 31}}metres$
- C${10^{ - 16}}\,metres$
- D${10^{ - 25}}\,metres$
✓
Answer
Correct option: A.
${10^{ - 33}}\,metres$
a
(a) $\lambda = \frac{h}{{mv}} = \frac{{6.63 \times {{10}^{ - 34}}}}{{60 \times {{10}^{ - 3}} \times 10}} = {10^{ - 33}}\,m$
(a) $\lambda = \frac{h}{{mv}} = \frac{{6.63 \times {{10}^{ - 34}}}}{{60 \times {{10}^{ - 3}} \times 10}} = {10^{ - 33}}\,m$
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