
In the above reaction, $3.9\, g$ of benzene on nitration gives $4.92\, g$ of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is............. $\%$. (Round off to the Nearest Integer).
(Given atomic mass: $C : 12.0\, u , H : 1.0\, u$$O : 16.0\, u , N : 14.0\, u )$

$CH_2(CO_2 Et)_2 $ $\xrightarrow[Et-I]{EtO^{\circleddash}} \,\,\xrightarrow[Et-I]{EtO^{\circleddash}}
\,\,\overset{Urea}{\rightarrow} $ $(P)$
(consider complete conversion)
(Where $Me$ is $- CH _{3}$ )