MCQ
The decreasing order of the ionisation potential in the following elements is
- A$Ne > Cl > P > S > Al > Mg$
- ✓$Ne > Cl > P > S > Mg > Al$
- C$Ne > Cl > S > P > Mg > Al$
- D$Ne > Cl > S > P > Al > Mg$
✓
Answer
Correct option: B.
$Ne > Cl > P > S > Mg > Al$
b
Ionization potential is the amount of energy required to remove an outermost valence electron from the atom.
Ionization potential is the amount of energy required to remove an outermost valence electron from the atom.
In moving down the group from top to bottom the ionization potential decreases and on moving from left to right in a period it is increases.
$Ne$ is the noble element, it has completely filled octet hence, it has the highest ionization potential.
Half-filled $( P )$ and completely filled configuration $( Mg )$ are the cause of the higher value of $I.E.$
The outer electronic configuration of $Mg$ and $Al$ are $3 s ^2$ and $3 s ^2\, 3 p ^1$ respectively.
The decreasing order of the ionization potential of the elements is:
$Ne\, >\, Cl\, >\, P\, > \,S \,>\, Mg\, >\, Al$
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