MCQ
The circumference of a circle whose area is $81\pi\text{r}^2,$ is:
  • A
    $9\pi\text{r}$
  • $18\pi\text{r}$
  • C
    $3\pi\text{r}$
  • D
    $81\pi\text{r}$

Answer

Correct option: B.
$18\pi\text{r}$
Let the radius of circle be $R$
$\therefore$ Area of circle $=\pi\text{R}^2$
$\Rightarrow81\pi\text{r}^2=\pi\text{R}^2$
$\Rightarrow\text{R}=\sqrt{81\text{r}^2}$
$\Rightarrow\text{R}=9\text{r}$
Now, circumference of circle $=2\pi\text{R}=2\pi(9\text{r})=18\pi\text{r}$

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