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8. mechanical properties of solids — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysics8. mechanical properties of solids1 Mark
MCQ
The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 \%$ is______ $\mathrm{m}$.

(Take density of sea water $=10^3 \mathrm{kgm}^{-3}$, Bulk modulus of rubber $=9 \times 10^8 \mathrm{Nm}^{-2}$, and $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )

  • A
    $15$
  • B
    $16$
  • C
    $17$
  • ✓
    $18$
✓

Answer

Correct option: D.
$18$
d
$\beta=\frac{-\Delta \mathrm{P}}{\frac{\Delta \mathrm{V}}{\mathrm{V}}}$

$\Delta \mathrm{P}=-\beta \frac{\Delta \mathrm{V}}{\mathrm{V}}$

$\rho \mathrm{gh}=-\beta \frac{\Delta \mathrm{V}}{\mathrm{V}}$

$10^3 \times 10 \times \mathrm{h}=-9 \times 10^8 \times\left(-\frac{0.02}{100}\right)$

$\Rightarrow \mathrm{h}=18 \mathrm{~m}$

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