MCQ
The derivative of $x^{2 x}$ w.r.t. $x$ is
  • A
    $x^{2 x-1}$
  • B
    $2 x^{2 x} \log x$
  • C
    $2 x^{2 x}(1+\log x)$
  • D
    $2 x^{2 x}(1-\log x)$

Answer

Let $y=x^{2 x}$
Taking log on both sides, we get
$
\log y=2 x \log x
$
Differentiating both sides w.r.t. $x$, we get
$
\begin{aligned}
& \frac{1}{y} \frac{d y}{d x}=2\left\{x \cdot \frac{1}{x}+\log x \cdot 1\right\} \\
\Rightarrow & \frac{d y}{d x}=2 y\{1+\log x\}=2 x^{2 x}(1+\log x)
\end{aligned}
$

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