The diameter of a circle described by 9x^ 2 +9y^2=16 is: - Vidyadip

MCQ

The diameter of a circle described by $\text{9x}^{2}+\text{9y}^2=16$ is:

A
$\frac{16}{9}$
B
$\frac{4}{3}$
C
$4$
✓
$\frac{8}{3}$

✓

Answer

Correct option: D.

$\frac{8}{3}$

Equation of circle is $\text{9x}^{2}+\text{9y}^2=16$
$\Rightarrow\text{x}^2+\text{y}^2=\frac{16}{9}$
$\Rightarrow\text{x}^2+\text{y}^2=(\frac{4}{3})^2$
$\therefore$ Radius of the circle $=\frac{4}{3}$
$\therefore$ Diameter of the circle $=\frac{4\times2}{3} = \frac{8}{3}$

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