Question
The difference between the compound interest and the simple interest on a certain sum for 3 years at 10% per annum is Rs. 93. Find the sum.

Answer

$\therefore$ Simple interest (S.I) $=\frac{\text{prt}}{100}$
$=\frac{100\times10\times3}{100}=\text{Rs. }30$
Amount (A) $=\text{P}\Big(1+\frac{\text{r}}{100}\Big)^{\text{n}}$
$=\text{Rs. }100\Big(1+\frac{10}{100}\Big)^3$
$=\text{Rs. }100\times\Big(\frac{11}{10}\Big)^3$
$=\text{Rs. }100\times\frac{11}{10}\times\frac{11}{10}\times\frac{11}{10}$
$=\text{Rs. }\frac{1331}{10}$
$\therefore$ C.I = A - P $=\text{Rs. }\frac{1331}{10}-\text{Rs. }100$
$=\text{Rs. }\frac{331}{10}$
Difference between C.I and S.I
$=\text{Rs. }\frac{1331}{10}-\text{Rs. }30=\text{Rs. }\frac{31}{10}$
If difference is $=\text{Rs. }\frac{31}{10},$ then sum
and if difference is Rs. 93 then sum
$=\text{Rs. }\frac{100\times93\times10}{31}$
$=\text{Rs. }3000$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Draw a rectangle ABCD such that l(AB) = 6.0 cm and l(BC) = 4.5 cm.
Draw a histogram to represent the following data:
Monthly salary (in Rs.)
Number of teachers
5600-5700
8
5700-5800
4
5800-5900
3
5900-6000
5
6000-6100
2
6100-6200
3
6200-6300
1
6300-6400
2
Find the area of a rhombus, side of which measures 20cm and one of whose diagonals is 24cm.
Sudhir’s present age is 5 more than three times the age of Viru. Anil’s age is half the age of Sudhir. If the ratio of the sum of Sudhir’s and Viru’s age to three times Anil’s age is 5:6, then find Viru’s age.
Various modes of transport used by 1260 students in a given school are given below:
School bus
Private bus
Bicycle
Rickshaw
On foot
350
245
210
175
280
Represent the above data by a pie chart.
Rakesh lent out Rs. 10000 for 2 years at 20% per annum, compounded annually. How much more he could earn if the interest be compounded half-yearly?
Solve the following equation and also check your result in case:
$\frac{3}{4}\text{x}+4\text{x}=\frac{7}{8}+6\text{x}-6$
In a parallelogram ABCD, AB = 10cm, AD = 6cm. The bisector of $\angle\text{A}$ meets DC in E. AE and BC produced meet at F. Find the length of CF.
ABC is a right-angled triangle and O is the mid-point of the side opposite to the right angle. Explain why O is equidistant from A, B and C.
A car with speed $60 \mathrm{~km} / \mathrm{hr}$ takes 8 hours to travel some distance. What should be the increase in the speed if the same distance is to be covered in $7 \frac{1}{2}$ hours?