- A$Rs. 360$
- B$Rs. 300$
- ✓$Rs. 180$
- D$Rs. 200$
It is given that,
$\operatorname{Sum}\left(P_1\right)= Rs. 1000$
Rate $\left(R_1\right)=12 \%$
Time $\left(T_1\right)=3$ years
$\mathrm{I}_1=\frac{\mathrm{P}_1 \times \mathrm{R}_1 \times \mathrm{T}_1}{100}$
$=\frac{1000 \times 12 \times 3}{100}$
$=$ Rs. $360 \ldots (i)$
Sum $\left(P_2\right)= Rs. 1500$
Rate $\left(R_2\right)=8 \%$
Time $\left(T_2\right)=1 \frac{1}{2}$ year $=\frac{3}{2}$ year
$\mathrm{I}_2=\frac{\mathrm{P}_2 \times \mathrm{R}_2 \times \mathrm{T}_2}{100}$
$=\frac{1500 \times 8 \times 3}{100 \times 2}$
$=$ Rs. $180 \ldots (ii)$
Subtracting $(ii)$ from $(i),$ we get
$I_2-I_1=$ Rs. $360- Rs. 180$
$=Rs. 180$
Hence, the correct option is $(c).$
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