MCQ
The difference in energy between the molecular orbital formed and the combining atomic orbitals is called
- ABond energy
- BActivation energy
- ✓Stabilization energy
- DDestabilization energy
✓
Answer
Correct option: C.
Stabilization energy
c
Stabilization Energy is defined as the energy of the electron configuration in the ligand field minus the energy of the electronic configuration in the isotropic field
Stabilization Energy is defined as the energy of the electron configuration in the ligand field minus the energy of the electronic configuration in the isotropic field
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The correct statement$(s)$ about the following sugars ${X}$ and ${Y}$ is$(are)$
→$(A)$ ${X}$ is a reducing sugar and ${Y}$ is a non-reducing sugar
$(B)$ ${X}$ is a non-reducing sugar and ${Y}$ is a reducing sugar
$(C)$ The glucosidic linkages in ${X}$ and ${Y}$ are $\alpha$ and $\beta$, respectively
$(D)$ The glucosidic linkages in ${X}$ and ${Y}$ are $\beta$ and $\alpha$, respectively
$SnCl_2$ acts as a reducing agent
→The decomposition of ${N_2}{O_4}$ to $N{O_2}$ is carried out at $280\,K$ in chloroform. When equilibrium has been established, $0.2$ $mol$ of ${N_2}{O_4}$ and $2 \times {10^{ - 3}}$ $mol$ of $N{O_2}$ are present in $2$ litre solution. The equilibrium constant for reaction ${N_2}{O_4}$ $\rightleftharpoons$ $2N{O_2}$ is
→The bond angle in $s{p^2}$ hybridisation is
→When phthalic acid is heated, phthalic anhydride is formed, $IUPAC$ name of phthalic anhydride is?
→A solution containing $30\,gms$ of non-volatile solute in exactly $90\,gm$ water has a vapour pressure of $21.85 \,\,mm\,Hg$ at ${25\,^o}C$. Further $18 \,gms$ of water is then added to the solution. The resulting solution has a vapour pressure of $ 22.15\,\,mm\,Hg$ at ${25\,^o}C$. Calculate the molecular weight of the solute
→Aqueous solution of $FeSO_4$ gives tests for both $Fe^{2+}$ and $SO_4^{2-}$ but after addition of excess of $KCN,$ solution ceases to give test for $Fe^{2+}.$ This is due to the formation of
→For an electron if the uncertainty in velocity is $\Delta \nu $, the uncertainty in its position $(\Delta x)$ is given by
→For the following reactions . . .Which of the following statements is correct ?
→$(A)\,\,CH_3CH_2CH_2Br + KOH \rightarrow CH_3CH CH_2 + KBr + H_2O$
Which of following statement is correct ?