Question
The difference of the squares of two consecutive numbers is their sum.
✓
Answer
TrueSolution:
Let $n$ and $n + 1$ be two consecutive numbers, then their sum $= n + n + 1 = 2n + 1$
Now, the difference of their squares,
$(n+1) 2-n^2=n^2+1+2 n-n^2$
Let $n$ and $n + 1$ be two consecutive numbers, then their sum $= n + n + 1 = 2n + 1$
Now, the difference of their squares,
$(n+1) 2-n^2=n^2+1+2 n-n^2$
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