MCQ
The differential coefficient of ${x^6}$ with respect to ${x^3}$ is
- A$5{x^2}$
- ✓$2{x^3}$
- C$5{x^5}$
- D$3{x^3}$
$\therefore \frac{{dy}}{{dz}} = \frac{{dy/dx}}{{dz/dx}} = \frac{{6{x^5}}}{{3{x^2}}} = 2{x^3}$
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$(A)$ $a+b=4$
$(B)$ $a-b=2$
$(C)$ The length of the diagonal $P R$ of the parallelogram $P Q R S$ is $4$
$(D)$ $\overrightarrow{ w }$ is an angle bisector of the vectors $\overrightarrow{ PQ }$ and $\overrightarrow{ PS }$