The differential equation ( d^2 y d x^2 )^2 - ( dy dx )^ 1/2 = y^… - Vidyadip

MCQ

The differential equation ${\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^2} - {\left( {\frac{{dy}}{{dx}}} \right)^{1/2}} = {y^3}$ has the degree

A
$1/2$
B
$2$
C
$3$
✓
$4$

✓

Answer

Correct option: D.

$4$

d
(d) From the given equation, ${\left( {{{\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)}^2} - {y^3}} \right)^2} = \frac{{dy}}{{dx}}$.
Hence, it is obvious from the equation that degree is $4$.

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