MCQ
The differential equation $x{\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^3} + {\left( {\frac{{dy}}{{dx}}} \right)^4} + y = {x^2}$ is of
  • Degree $3$ and order $2$
  • B
    Degree $1$ and order $1$
  • C
    Degree $4$ and order $3$
  • D
    Degree $4$ and order $4$

Answer

Correct option: A.
Degree $3$ and order $2$
a
(a) Given differential equation, $x{\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^3} + {\left( {\frac{{dy}}{{dx}}} \right)^4} + y = {x^2}$

In this equation order of highest derivative is $2,$

Hence order $ = 2$ and degree of highest derivative $ = 3$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $A=\left[\begin{array}{lll}1 & 0 & 1 \\ 0 & 0 & 0 \\ 1 & 0 & 1\end{array}\right]$, then $A^2=$ ?
A box contains 6 nails and 10 nuts. Half of the nails and half of the nuts are rusted. If one iten is chosen ar random, the probability that it is rusted or is nail is
  1. $\frac{3}{16}$
  2. $\frac{5}{16}$
  3. $\frac{11}{16}$
  4. $\frac{14}{16}$
A function f from the set of natural numbers to the set of integers defined by $\text{f(n)}\begin{cases}\frac{\text{n}-1}{2},&\text{when n is odd}\\-\frac{\text{n}}{2},&\text{when n is even}\end{cases}$ is:
  1. Neither one-one nor onto.
  2. One-one but not onto.
  3. Onto but not one-one.
  4. One-one and onto.
If $\hat a,\,\hat b$ and $\hat c$ are unit vectors satisfying $\hat a\, - \,\sqrt 3 \hat b + \hat c\, = \,\vec 0,$ then the angle between the  vectors $\hat a$ and $\hat c$ is 
Choose the correct answer in Exercise.

$\int\sqrt{\text{x}^2-8\text{x}+7}\text{dx}$ is equal to

  1. $\frac{1}{2}(\text{x}-4)\sqrt{\text{x}^2-8\text{x}+7}+9\text{log}\Bigg|\text{x}-4+\sqrt{\text{x}^2-8\text{x}+7}\Bigg|+\text{C}$

  2.  $\frac{1}{2}(\text{x}+4)\sqrt{\text{x}^2-8\text{x}+7}+9\text{log}\Bigg|\text{x}+4+\sqrt{\text{x}^2-8\text{x}+7}\Bigg|+\text{C}$

  3. $\frac{1}{2}(\text{x}-4)\sqrt{\text{x}^2-8\text{x}+7}-3\sqrt2\text{log}\Bigg|\text{x}-4+\sqrt{\text{x}^2-8\text{x}+7}\Bigg|+\text{C}$

  4. $\frac{1}{2}(\text{x}-4)\sqrt{\text{x}^2-8\text{x}+7}-\frac{9}{2}\text{log}\Bigg|\text{x}-4+\sqrt{\text{x}^2-8\text{x}+7}\Bigg|+\text{C}$

The function $f(x)=x+\sin x$ is
$\int_{ - 4}^4 {|x + 2|\,dx} = $
If centroid of the tetrahedron $OABC$, where $A,B,C$are given by $(a, 2, 3),(1, b, 2)$ and $(2, 1, c)$ respectively be $(1, 2, -1)$, then distance of $P(a,b,c)$ from origin is equal to
$\int\limits_{2}^{2} \mid\text{x}\mid\text{dx}=$
  1. 0
  2. 2
  3. 1
  4. 4
Let $\quad P_1=I=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right], \quad P_2=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0\end{array}\right], \quad P_3=\left[\begin{array}{lll}0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1\end{array}\right], \quad P_4=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0\end{array}\right], \quad P_5=\left[\begin{array}{lll}0 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 0\end{array}\right]$,

$P_6=\left[\begin{array}{lll}0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0\end{array}\right]$ and $X=\sum_{k=1}^6 P_k\left[\begin{array}{lll}2 & 1 & 3 \\ 1 & 0 & 2 \\ 3 & 2 & 1\end{array}\right] P_k^{\top}$

where $P _{ K }^{ T }$ denotes the transpose of the matrix $P _{ K }$. Then which of the following options is/are correct?

$(1)$ $X -30 I$ is an invertible matrix

$(2)$ The sum of diagonal entries of $X$ is 18

$(3)$ If $X \left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]=\alpha\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$, then $\alpha=30$

$(4)$ $X$ is a symmetric matrix