Introduction to Physics — Physics STD 11 Science — Question

3. Pressure.
4. Energy per unit volume.

Explantion:

$\text{[Work done] = [ML}^2\text{ T}^{-2}]$

$\text{[Linear momentum] = [MLT}^{-1}]$

$\text{[Pressure] = [ML}^{-1}\text{T}^{-2}]$

$\text{[Energy per unit volume] = [ML}^{-1}\text{T}^{-2}]$

From the above, we can see that pressure and energy per unit volume have the same dimension, i.e., $\text{ML}^{-1}\text{T}^{-2}.$