MCQ
The dimensions of surface tension are
- A$[ML{T^{ - 1}}]$
- B$[M{L^2}{T^{ - 2}}]$
- ✓$[M{L^0}{T^{ - 2}}]$
- D$[M{L^{ - 1}}{T^{ - 2}}]$
✓
Answer
Correct option: C.
$[M{L^0}{T^{ - 2}}]$
c
(c)$T = \frac{F}{l} = \frac{{[ML{T^{ - 2}}]}}{{[L]}} = [M{L^0}{T^{ - 2}}]$
(c)$T = \frac{F}{l} = \frac{{[ML{T^{ - 2}}]}}{{[L]}} = [M{L^0}{T^{ - 2}}]$
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