MCQ
The diode shown in the circuit is a silicon diode. The potential difference between the points $A$ and $B$ will be.....$V$
- ✓$6$
- B$0.6$
- C$0.7$
- D$0$
✓
Answer
Correct option: A.
$6$
a
(a)In the given condition diode is in reverse biasing so it acts as open circuit. Hence potential difference between $A$ and $B$ is $ 6V$
(a)In the given condition diode is in reverse biasing so it acts as open circuit. Hence potential difference between $A$ and $B$ is $ 6V$
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