MCQ
The dipole moment of $o, p$ and $m-$ dichlorobenzene will be in the order
- A$o > p > m$
- B$p > o > m$
- C$m > o > p$
- ✓$o > m > p$
$o$-dichlorobenzene has a higher dipole moment due to a lower bond angle than the $m$-isomer. Hence, the order of increasing dipole moment is :
$p$-dichlorobenzene $\,<\, m$-dichlorobenzene $\,<\, o$-dichlorobenzene
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

| List $I$(Quantum Number) | List $II$(Information provided) |
| $A$. mı | $I$. Shape of orbital |
| $B$. $m_s$ | $II$. Size of orbital |
| $C$. $1$ | $III$. Orientation of orbital |
| $D$. $\mathrm{n}$ | $IV$. Orientation of spin of electron |
Choose the correct answer from the options given below :