MCQ
The directrix of the hyperbola is $\frac{{{x^2}}}{9} - \frac{{{y^2}}}{4} = 1$
- ✓$x = 9/\sqrt {13} $
- B$y = 9/\sqrt {13} $
- C$x = 6/\sqrt {13} $
- D$y = 6/\sqrt {13} $
where $e = \sqrt {\frac{{{b^2} + {a^2}}}{{{a^2}}}} = \frac{{\sqrt {{b^2} + {a^2}} }}{a}$
Directrix is, $x = \frac{{{a^2}}}{{\sqrt {{a^2} + {b^2}} }} = \frac{9}{{\sqrt {9 + 4} }}$
==> $x = 9/\sqrt {13} $
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