The displacement of a particle executing simple harmonic motion is given by

$\mathrm{y}=\mathrm{A}_{0}+\mathrm{A} \sin \omega \mathrm{t}+\mathrm{B} \cos \omega \mathrm{t}$

Then the amplitude of its oscillation is given by

  • A$\mathrm{A}_{0}+\sqrt{\mathrm{A}^{2}+\mathrm{B}^{2}}$
  • B$\sqrt{\mathrm{A}^{2}+\mathrm{B}^{2}}$
  • C$\sqrt{\mathrm{A}_{0}^{2}+(\mathrm{A}+\mathrm{B})^{2}}$
  • D$\mathrm{A}+\mathrm{B}$
NEET 2019, Medium
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