MCQ
The dissociation constants of two acids $HY$ and $HZ$ are $2.88 \times 10^{-4}$ and $1.8 \times 10^{-5}$ respectively. The relative strength of the acids will be :-
- A$1 : 4$
- ✓$4 : 1$
- C$1 : 16$
- D$16 : 1$
✓
Answer
Correct option: B.
$4 : 1$
b
Relative strength $=\sqrt{\frac{\mathrm{K}_{\mathrm{a}_{\mathrm{1}}}}{\mathrm{K}_{\mathrm{a}_{\mathrm{2}}}}}$
Relative strength $=\sqrt{\frac{\mathrm{K}_{\mathrm{a}_{\mathrm{1}}}}{\mathrm{K}_{\mathrm{a}_{\mathrm{2}}}}}$
$\sqrt{\frac{2.88 \times 10^{-\mathrm{4}}}{1.8 \times 10^{-\mathrm{5}}}}=\sqrt{\frac{16}{1}}=4: 1$
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