MCQ
The distance between $3^{rd}$ and $2^{nd}$ Bohr's orbits in the hydrogen atom is
- ✓$2.646\, \times \, 10^{-8}\, cm$
- B$2.116\, \times \, 10^{-8}\, cm$
- C$1.058\, \times\, 10^{-8}\, cm$
- D$0.529\, \times\, 10^{-8}\, cm$
$ = 0.529 \times 5$
$ = 2.645\,\mathop A\limits^o $
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$H_2 + F_2 \longrightarrow 2HF$
given that
Bond energy of $H-H$ bond $= 434\, kJ/mol$
Bond energy of $F-F$ bond $= 158\, kJ/mol$
Bond energy of $H-F$ bond $= 565\, kJ/mol$
.....$ kJ$