- A$2$
- B$3$
- C$4$
- ✓$5$
=$\sqrt {{{(3 - 7)}^2} + {{(2 - 5)}^2}} = \sqrt {16 + 9} = 5$ unit.
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Let $\mathrm{a}=1+\frac{{ }^2 \mathrm{C}_2}{3 !}+\frac{{ }^3 \mathrm{C}_2}{4 !}+\frac{{ }^4 \mathrm{C}_2}{5 !}+\ldots$, Then $\frac{2 b}{a^2}$ is equal to.........................
$x+y+z=5$ ; $x+2 y+3 z=\mu$ ; $x+3 y+\lambda z=1$
is constructed. If $\mathrm{p}$ is the probability that the system has a unique solution and $\mathrm{q}$ is the probability that the system has no solution, then :
$S _{1}=\{ z \in C :| z -1| \leq \sqrt{2}\}$ ; $S _{2}=\{ z \in C : \operatorname{Re}((1- i ) z ) \geq 1\}$ ; $S _{3}=\{ z \in C : \operatorname{Im}( z ) \leq 1\}$ Then the set $S _{1} \cap S _{2} \cap S _{3}$